Action of Sodium Hydroxide on Metallic Salt Solutions

Write the probable colour of the ammonium salts?

The pungent smell produced in the reaction of ammonium ions with $\mathrm{NaOH}$ is due to the formation of 

Write the chemical equation for the identification of ammonium ion using sodium hydroxide solution.

Sodium hydroxide cannot be used to identify :

Name the metal which reacts with sodium hydroxide solution, liberating hydrogen gas.

A white gelatinous precipitate is formed when this compound reacts with sodium hydroxide.

_____ and _____ ions give white precipitates with $\text{NaOH}$ solution which are soluble in excess of the reagent. 

Name the probable cation present in the following observation:

White precipitate insoluble in ${\mathrm{NH}}_4\mathrm{OH}$ but soluble in $\mathrm{NaOH}$.

On adding sodium hydroxide drop by drop to a solution of ferrous sulphate, a dirty green precipitate is formed. Write the chemical formula of the compound formed of this colour.

$\mathrm{A}: \mathrm{Fe}{\left(\mathrm{OH}\right)}_3 \mathrm{B}: \mathrm{Fe}{\left(\mathrm{OH}\right)}_2 \mathrm{C}: {\mathrm{Fe}}_2{\mathrm{O}}_3 \mathrm{D}: \mathrm{FeO}$ (Enter your correct answer as $\mathrm{A}, \mathrm{B}, \mathrm{C} \mathrm{or} \mathrm{D}$)

The colour of precipitate formed when sodium hydroxide is added to a solution of ferric chloride is _____.

The gas evolved when aluminium powder is mixed with sodium hydroxide solution is:

A white gelatinous precipitate is formed when this compound reacts with sodium hydroxide.

A pale green crystalline metallic salt dissolves freely in water and gives a brown precipitate on addition of aqueous $NaOH.$ The metallic salt solution also gives a black precipitate on bubbling $H_{2}S$ in acidic medium. An aqueous solution of this decolourises the purple colour of the permanganate solution. The metal in the metallic salt solution is:

Consider the following statements,
S₁ : Fe(OH)₃ and Cr(OH)₃ precipitates can be separated using NaOH + H₂O₂ but not by excess of NaOH alone.

S₂ : Ag₂CrO₄ precipitate is soluble in dilute HNO₃ and ammonia solution.

S₃ : both HgI₂ and BiI₃ precipitates form colourless soluble complexes with excess of potassium iodide solution.

S₄ : white precipitate of PbCl₂ is turned black by H₂S (not taken in excess) in saturated solution of KCl.

and arrange in the order of true / false.

$Fe{\left(OH\right)}_3$ can be separated from $Al{\left(OH\right)}_3$ by addition of

A metal M and its compound can given the following observed changes in a conseqquence of reaction,

$\text{M}\underset{{\text{HNO}}_3}{\overset{\text{Dil}}{\to }}\left[\text{Colourless solution}\right]\stackrel{\text{aq NaOH}}{\to }\left[\text{White ppt}\right]\stackrel{\underset{\text{aq NaOH}}{\text{excess}}}{\to }\left[\text{Colourless solution}\right]\stackrel{{\text{H}}_2\text{S}}{\to }\left[\text{White ppt}\right]$

then metal M will be